ABCD is a square with each side measuring 144 cm. M is a point on CB such that CM=36 cm. If N is a variable point on the diagonal DB, find the least value of CN+MN.
Answer:
180 cm
- Given, BC=144 cm and CM=36 cm
⟹BM=CB−CM=144−36=108
Let's join A to N - Since △ADN≅△CDN[By SAS criterion]∴
\implies \space AN + MN = CN + NM
Observe that the value of AN + NM is least when ANM is a straight line. - Now, if ANM is a straight line, then \triangle AMB is a right-angled triangle.
\therefore by Pythagoras theorem,
From step 2, we have AN + MN = CN + NM.Least value of AN + NM \begin{align} & = \sqrt{ AB^2 + BM^2 } \\ & = \sqrt{ 144^2 + 108^2 } \\ & = 180 \end{align} - Hence, the least value of CN + MN is 180 \space cm.