ABCD is a square with each side measuring 144 cm. M is a point on CB such that CM=36 cm. If N is a variable point on the diagonal DB, find the least value of CN+MN.
D C B A M N


Answer:

180 cm

Step by Step Explanation:
  1. Given, BC=144 cm and CM=36 cm
    BM=CBCM=14436=108
    Let's join A to N
    D C B A M N
  2. Since ADNCDN[By SAS criterion]
    \implies \space AN + MN = CN + NM
    Observe that the value of AN + NM is least when ANM is a straight line.
  3. Now, if ANM is a straight line, then \triangle AMB is a right-angled triangle.
    \therefore by Pythagoras theorem,
    Least value of AN + NM \begin{align} & = \sqrt{ AB^2 + BM^2 } \\ & = \sqrt{ 144^2 + 108^2 } \\ & = 180 \end{align}
    From step 2, we have AN + MN = CN + NM.
  4. Hence, the least value of CN + MN is 180 \space cm.

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