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Two coins are tossed simultaneously. What is the probability of getting at least one tail?

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Answer:

$\dfrac { 3 } { 4 }$

Step by Step Explanation:

1. When two coins are tossed simultaneously, all possible outcomes are $HH, HT, TH, TT$.
   
   The total number of all possible outcomes = $4$.
   
   
2. Let $E$ be the event of getting at least one tail.
   
   Therefore, $E$ is the event of getting $1$ tail or $2$ tails.
   
   So, the favourable outcomes from $HH, HT, TH, TT$ are $HT, TH$ and $TT$.
   
   Number of favourable outcomes = 3. $$\begin{aligned} \therefore \space P(\text{getting at least one tail}) = P(E) = \dfrac { 3 } { 4 }. \end{aligned}$$
3. Therefore, the probabilty of getting at least one tail is $\dfrac { 3 } { 4 }$.

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