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What is the sum of all interior angles of a polygon of $10$ sides$?$

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Answer:

$16 \text{ right angles }$

Step by Step Explanation:

1. We know that the sum of all interior angles of a polygon of $n$ sides is $(2n - 4)$ right angles.
2. $$\begin{align} \text{ Sum of all interior angles of the polygon of } 10 \text{ sides } &= ( 2 \times 10 - 4 ) \text{ right angles } \\ &= 16 \text{ right angles } \end{align}$$

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